Dobrý den,chtěl jsem se zeptat,jestli byste mi neporadili s jednim problémem nad kterým si lámu hlavu už týden.Mam zadani teto ulohy:
Napište v jazyce C implementaci zjednodušené funkce sprintf dle následujícího manuálu:
Deklarace a popis chování
int Sprintf(char *str, const char *format, ...);
DESCRIPTION
The function produces output according to a format as described below and writes it to the character string str.
The function writes the output under the control of a format string that specifies how subsequent arguments are converted for output.
Return value
Upon successful return, the function return the number of characters printed (not including the trailing ’\0’ used to end output to strings). If an output error is encountered, a negative value is returned.
Format of the format string
The format string is a character string, beginning and ending in its initial shift state, if any. The format string is composed of zero or more directives: ordinary characters (not %), which are copied unchanged to the output stream; and conversion specifications, each of which results in fetching zero or more subsequent arguments. Each conversion specification is introduced by the character %, and ends with a conversion specifier. In between there may be an optional length modifier.
The arguments must correspond properly (after type promotion) with the conversion specifier. By default, the arguments are used in the order given, where each conversion specifier asks for the next argument (and it is an error if insufficiently many arguments are given).
The length modifier
Here, ‘integer conversion’ stands for d, i, o, u, x, or X conversion.
hh
A following integer conversion corresponds to a signed char or unsigned char argument.
h
A following integer conversion corresponds to a short int or unsigned short int argument.
l
(ell) A following integer conversion corresponds to a long int or unsigned long int argument.
The conversion specifier
A character that specifies the type of conversion to be applied. The conversion specifiers and their meanings are:
d,i
The int argument is converted to signed decimal notation.
o,u,x,X
The unsigned int argument is converted to unsigned octal (o), unsigned decimal (u), or unsigned hexadecimal (x and X) notation. The letters abcdef are used for x conversions; the letters ABCDEF are used for X conversions.
c
The int argument is converted to an unsigned char, and the resulting character is written.
s
The const char* argument is expected to be a pointer to an array of character type (pointer to a string). Characters from the array are written up to (but not including) a terminating NUL character.
p
The void * pointer argument is printed in hexadecimal (as if by 0x%x or 0x%lx).
%
A ‘%’ is written. No argument is converted. The complete conversion specification is ‘%%’.
Zdrojovy kod mám takovýhle:
[code]
#include <stdlib.h>
#include <stdio.h>
#include <stdarg.h>
#include <string.h>
enum
{ eNone = 0x00, efShort = 0x02, efLong = 0x04,
efChar = 0x08, eInt = 0x10, eString = 0x20,
efUnsDec = 0x40, eChar = 0x80, eOctal = 0x200,
eHexa = 0x400, eBigHexa = 0x800, ePointer = 0x1000
};
int Sprintf(char *str, const char *format, ...)
{
va_list l;
char * pch = (char*)format, *p1, *p2;
char* start = str;
char temp[128];
long num;
unsigned long n;
int i, t, s, len = 0;
if(str == 0) return -1;
va_start(l, format);
for (;*pch;)
{ if(*pch == '%')
{ for(pch = pch +1;*pch >= '0' && *pch<='9'; )
len = len * 10 + *pch++ - '0';
s = eNone;
if(*pch == 'l'){ s = efLong; pch ++;}
if(*pch == 'h'){ s = efShort; pch ++;}
if(s == efShort && *pch == 'h'){ s = efChar; pch ++;}
switch(*pch)
{
case 'i':
case 'd': s |= eInt; pch ++; break;
case 's': s = eString;pch ++; break;
case 'u': s |= efUnsDec;pch ++; break;
case 'c': s = eChar; pch ++; break;
case 'o': s |= eOctal;pch++; break;
case 'x': s |= eHexa;pch++; break;
case 'X': s |= eBigHexa;pch++;break;
case 'p': s = ePointer;pch++; break;
};
if(s == eNone) *str++ = *pch++;
else if(s == eString)
{ p1 = va_arg(l,char*);
for(p2=p1;*p2; ++p2, ++str)
{ if(len && (p2-p1) >= len) break;
*str = *p2;
}
}
else if(s == ePointer)
{ *str++ ='0';*str++ = 'x';
n = (unsigned long)va_arg(l, void*);
for(i=0; n > 0;n /= 16, ++i)
{ t = n % 16;
if(t > 9) { t %= 10; temp[i] = 'a'+t;}
else temp[i] = t + '0';
}
for(;i < 2*sizeof(void *);++i) temp[i] = '0';
for(;i > 0;) *str++ = temp[--i];
}
else if(s == eChar)
{ *str++ = (unsigned char)va_arg(l, int);
}
else {
num = va_arg(l, long);
if(s & efShort) num = (s & efUnsDec)?(unsigned short)num:(short)num;
else if(s & efChar) num = (s & efUnsDec)?(unsigned char)num:(char)num;
if(s & eInt)
{ num = (int)num;
n = num < 0 ? -num : num;
if(num < 0) *str++ = '-';
for(i=0; n > 0; n /= 10, ++i)
temp[i] = n % 10 + '0';
}
else if(s & eOctal)
{ n = (num < 0) ? -num : num;
for(i=0; n > 0; n /= 8, ++i)
temp[i] = n % 8 + '0';
if(num < 0) temp[i++] = '-';
}
else if((s & eHexa)||(s & eBigHexa))
{ n = (num < 0) ? -num : num;
for(i=0; n > 0;n /= 16, ++i)
{ t = n % 16;
if(t > 9) { t %= 10; temp[i] = (s & eBigHexa)?'A'+t:'a'+t;}
else temp[i] = t + '0';
}
if(num < 0) temp[i++] = '-';
}
else
{
if(s & efUnsDec)n = num;
else{
if(num < 0)
n = -num;
else
n = num;
}
if(num < 0 && !(s & efUnsDec)) *str++ = '-';
for(i=0; n > 0; n /= 10, ++i)
temp[i] = n % 10 + '0';
}
for(;i > 0; ) *str++ = temp[--i];
}
}
else
*str++ = *pch++;
}
*str = '\0';
va_end(l);
return str - start;
}
int main(int argc, char** argv[])
{ char buf[512];
int len = Sprintf(buf, "%d-%d=%d", -1, 4, -1-4);
printf("%s\nVytisknuto %d znaku.\n", buf, len);
len = Sprintf(buf, "20%% ze 100 je %d", 100/5);
printf("%s\nVytisknuto %d znaku.\n", buf, len);
len = Sprintf(buf, "-1000 v osmickove soustave je %o", -1000);
printf("%s\nVytisknuto %d znaku.\n", buf, len);
len = Sprintf(buf, "1000 v hexa soustave je %x nebo %X.", 1000, 1000);
printf("%s\nVytisknuto %d znaku.\n", buf, len);
len = Sprintf(buf, "1000 v hexa soustave je %x nebo %X.", 1000, 1000);
printf("%s\nVytisknuto %d znaku.\n", buf, len);
len = Sprintf(buf, "Znak %c nebo %hhc.", 165, 165);
printf("%s\nVytisknuto %d znaku.\n", buf, len);
len = Sprintf(buf, "Adresa buf je %p.", buf);
printf("%s\nVytisknuto %d znaku.\n", buf, len);
len = Sprintf(buf, "1. dva znaky ze slova %s jsou %2s\n", "Pepiku", "Pepiku");
printf("%sVytisknuto %d znaku.\n", buf, len);
system ("PAUSE");
return 0;
}
[/code]
přes automat kterymu to ucitelo posilam se vypsie protokol s timto vypisem
[code]
--- gcc-4.0 prelozeno ---
--- gcc-2.95 prelozeno ---
--- protokol "./test.1.bin" ---
59: "-109725520, -109725520, 4185241776, 0-642443520, 0x-68a4750" (60: "-109725520, -109725520, 4185241776, 037135334260, 0xf975b8b0")
136: "-80, 176, -18256, 47280, -109725520, 4185241776, -109725520, 4185241776 80, 80, 18256, 18256, 109725520, 109725520, 109725520, 109725520" (136: "-80, 176, -18256, 47280, -109725520, 4185241776, -109725520, 4185241776 80, 80, 18256, 18256, 109725520, 109725520, 109725520, 109725520")
36: "0, "Chrchly Chrchly", 48, 0xbf89af28" (36: "0, "Chrchly Chrchly", 48, 0xbf89af28")
! Chyba: 1
---
--- protokol "./test.2.bin" ---
59: "-109725520, -109725520, 4185241776, 0-642443520, 0x-68a4750" (60: "-109725520, -109725520, 4185241776, 037135334260, 0xf975b8b0")
136: "-80, 176, -18256, 47280, -109725520, 4185241776, -109725520, 4185241776 80, 80, 18256, 18256, 109725520, 109725520, 109725520, 109725520" (136: "-80, 176, -18256, 47280, -109725520, 4185241776, -109725520, 4185241776 80, 80, 18256, 18256, 109725520, 109725520, 109725520, 109725520")
36: "0, "Chrchly Chrchly", 48, 0xbfc1c4f4" (36: "0, "Chrchly Chrchly", 48, 0xbfc1c4f4")
! Chyba: 1
---
[/code]
u toho vypisu mám nějaky ty čisla,pak mam taky čisla a znaky v závorkách,to co je v závorce je správný výpis jak by to mělo správně vypisovat,takže z toho poznám kde co je špatně.špatně je jen na prvnich řádkách poslední dvě číselné kombinace.
No a v tom je ten problem,chybu mám v číslech asi někde v hh, h a l.říkal mi to aspon kamarád,jelikoz ja na to neprisel.Nemohli byste mi s tím prosim Vás někdo pomoc jak to mám spravit aby to vypisovalo správně.Byl bych Vám moc vděčný. |
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